An ionized hydrogen atom $($net charge $=+$e$,$ where e is the charge of the proton$)$ is accelerated through a potential difference of $6\mathrm{.}0$ V$.$ What is the increase in kinetic energy of the atom? $($Note: an electron$-$Volt, abbreviated eV$,$ is a unit of energy equal to the charge $+$e of a proton times $1$ Volt$).$

$0\mathrm{.}67$ eV$4$ eV$24$ eV$0$ eV$6$ eV