Question: Work Done by a Variable Force over a Curved Path An object moves along a parabolic path y= (0.5 m-x from the origin A
Work Done by a Variable Force over a Curved Path An object moves along a parabolic path y= (0.5 m-x from the origin A = (0, 0) to the point B = (2 m, 2 m) under the action of a force F = (5 N/m)y i + (10 N/m)xj (Figure 7.6). Calculate the work done. y(m)4 (2.2) Fx. ) (0, 0) x(m) Figure 7.6 The parabolic path of a particle acted on by a given force.
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the particle moves on path y05x 2 Force acting is F5y 10x we repl... View full answer
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