Analyze the frame shown in Figure below using flexibility method of analysis. Take EI as constant.

w=25.84 kN/m

Transcribed Image Text:

40 kN+ 25.84 KN/m w = 6 m 30KN 80 kN- 4.5m E, A, I = constant 6 m E = 30 GPa A = 75,000 mm2 I= 4.8(10) mm* 9 m 40 kN+ 25.84 KN/m w = 6 m 30KN 80 kN- 4.5m E, A, I = constant 6 m E = 30 GPa A = 75,000 mm2 I= 4.8(10) mm* 9 m

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Free Body Diagram of the frame Number of unknowns U 6 Number of equations of equilibrium E 3 Thus static degree of indeterminacy of frame is given by D si UE D si 63 D si 3 Step 1 Select V E H E and M ... View the full answer