Question: A property is being transported through a fluid at steady-state through a constant cross-sectional area. At point 1 the concentration I is 2.78 x

A property is being transported through a fluid at steady-state through a constant cross-sectional area. At

A property is being transported through a fluid at steady-state through a constant cross-sectional area. At point 1 the concentration I is 2.78 x 10- amount of property/m and 1.50 x 10- at point 2 at a distance of 2.0 m away. The diffusivity depends on concentration I as: & = 0.150 + 1.65r. b. a. Calculate the steady-state flux if the two points were separated by 3.5 m, but with the same concentrations. How does the flux vary with the distance between the points? Calculate the steady-state flux if the concentration at point 2 was 1.50 x 10- amount of property/m, using the original distance (2.0 m). How does the flux vary with the difference in concentration?

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To determine the steadystate fluxwe need to consider the equation for mass balanceThe mass balance equation for a steadystate process is given by C t DC 0 where D is the diffusivityC is the concentrat... View full answer

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