Question: Answer: Submit All Answers 7. [1pt] * 7 A frictionless pulley with zero mass is attached to the ceiling. Mass .M, - 0.227 kg is
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Answer: Submit All Answers 7. [1pt] * 7 A frictionless pulley with zero mass is attached to the ceiling. Mass .M, - 0.227 kg is being accelerated downward with 1.24 m's?. Calculate the mass m, 1 2 Submit All Answers 8. [1pt] # 72 Am You only have 8 tries. Draw free body diagrams! Answer True, False, or Cannot tell to each of the four statements below. E.g, if the answer to the first statement is "true' and to the rest, "cannot tell', enter TCCC. Be careful about the signs of the acceleration (x is posithe to the right, y is positive up)! 2 b. Block 1 rests on a frictionless table. In case A, a 10 N weight is attached; in case B, a 10 N force is applied to the rope. The ter n the block is released. 1 1 77 ION 10 N Tension B diagram below, then joy) = 8- 1 2 The diagram below shows two blocks, I and 2, at rest, connected to a rope and pulley system. There is friction between the blocks, but block 2 rests on a frictionless surface. An external force F.., is applied; the tension in the rope is I and the frictional force is F. (Draw free body diagrams!) If the blocks move, then 27-F. 1 2 Answer Submit All Answers9. [1pt] * #4 . Jf, and .M, are two masses connected as shown. The pulley and the incline are f M, (3.00 kg) accelerates downwards at 291 m's', and that @ - 27.0'. Answer: Submit All Answers 10. [1pt] # #ty Two masses M, = 8.31 kg and .M, = 8.33 kg are connected with a massless string over two massless pulleys, with one end of the string attached to a solid table. The pulleys and surfaces are frictionless. What is the magnitude of the acceleration of mass M? answer Submit Al Answers 11. [1pt] * # t A block of mass m, is attached to a block of mass m, by a ss. When the blocks are let aswer to the first question is A, to the second, C, and to the third, D, enter ACD. You only have 6 tries! A) a, = 20/m, 8 B) a, - 8-20m. D) a, - Dim,-g E) , = Im, G) a, = Tim,+gm, (2m) H) a,, = 126, L) a, - Tim,+gmi'm, Na= Im 0) , = 207m, P) a, = 27im,+gm_m, R) a - -20 s) a = 201m;-8 1) a, - 21im, +gm/my V) a, = 2Tim, X) a, = -20% Note that in these expressions, g is the magnitude of the acceleration due to gravity. 1) Select the correct expression for the relationship between the accelerations of blocks 1 and 2. in) Select the correct expression that describes how the magnitude of the acceleration of block 1, a,, depends on the tension in the rope, I. il) Select the correct expression that describes how the magnitude of the acceleration of block 2, a,, depends on the tension in the rope, I. Answer Submit Al Answers 12. [1pt] # # tz If m, " 2.20 kg and my = 1.80 kg. find the magnitude of the acceleration of block 1, a,, once the blocks are released. Answer: Submit Al Answers
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