Apply the second condition for equilibrium $($step $3).$

${}_i={}_R+{}_F+{}_{BB}=0$

$R(0)+F(0\mathrm{.}0292m)-(50\mathrm{.}6N)(0\mathrm{.}341m)=0$

$F=,N$

$F=,lb$

Apply the first condition for equilibrium $($step $4).$

$F_y=F+R-50\mathrm{.}6N=0$

$R=F-50\mathrm{.}6N=591N-50\mathrm{.}6N$

$R=$

$R=,N$

Exercise $8\mathrm{.}6$

Hints: Getting Started $|$ I$\text{'}$m Stuck

Suppose you wanted to limit the force acting on your joint to a maximum value of

$8\mathrm{.}23{10}^{2}N.$

$($a$)$ Under these circumstances, what maximum weight would you attempt to lift?

$F_{\text{m}\text{a}\text{x}}=$

$($b$)$ What force would your biceps apply while lifting this weight?

$F_{\text{b}\text{i}\text{c}\text{e}\text{p}\text{s}}=$