Assume that i16, and i16k are int16+ data types and i8, is a int8+ data type....

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Assume that i16, and i16k are int16+ data types and i8, is a int8+ data type. All variables are located in near RAM. Convert the following code segment to a PIC24 instruction sequence. i16_k = (int16_t) i8 p + (i16. << 1) - 256; Assume that i16, and i16k are int16+ data types and i8, is a int8+ data type. All variables are located in near RAM. Convert the following code segment to a PIC24 instruction sequence. i16_k = (int16_t) i8 p + (i16. << 1) - 256;

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In the given code fragment you are playing out a few procedure on factors of various information types int8 and int16 and afterward relegating the outcome to an int16 variable To change this code over ... View the full answer