Question: Assuming that the following function is defined properly: ( begin{array}{l} text { def calcutale_it(a, b, c): } text { if } a % c=0:
Assuming that the following function is defined properly: \( \begin{array}{l} \text { def calcutale_it(a, b, c): } \\ \text { if } a \% c=0: \\ \text { print(a** }(a / / b))\end{array} \) What will be printed in the following function call if a is set to 1,b is set to 2, and c is set to 3 ? calcutale_it (a,b,c) 5.19615242 nothing 3 error
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