Question: Assuming the following code: int x = myfunction 1 ( ) ; a rbitrary value * int y = myfunction 2 ( ) ; a

Assuming the following code:
int x= myfunction 1();arbitrary value*
int y= myfunction2();arbitrary value*
unsigned ux=x;
unsigned uy=y;
The following statement always evaluates to 1(True or False):
(x**x)0
True
False
Assuming the following code: int x= myfunction 1();arbitrary value* int y=

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