At time $\backslash ($ t$=0\backslash ),$ an electron with kinetic energy $14$ keV moves through $\backslash ($ x$=0\backslash )$ in the positive direction of an $\backslash ($ x $\backslash )$ axis that is parallel to the horizontal component of Earth's magnetic field. The field's vertical component is downward and has magnitude $\backslash (47\mathrm{.}0\backslash$mu $\backslash$mathrm$\{$~T$\}\backslash ).($a$)$ What is the magnitude of the electron's acceleration in meters per second squared, due to the magnetic field? $($b$)$ What is the electron's distance from the $\backslash ($ x $\backslash )$ axis in centimeters when the electron reaches coordinate $\backslash ($ x$=19\backslash$mathrm$\{$~cm$\}\backslash )?$