Question: At what point does the line normal to the graph of y = 3x2 - (5 + 4x) at (1, -6) intersect the parabola a


At what point does the line normal to the graph of y = 3x2 - (5 + 4x) at (1, -6) intersect the parabola a second time? Hint: The normal line is perpendicular to the tangent line. If two lines are perpendicular their slopes are negative reciprocals -- i.e. if the slope of the first line is m then the slope of the second line is -1/m
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