At what pressure does the mean free path of kr atoms (d = 3.16 × 10⁻¹⁰ m) become comparable with the diameter of a Kr atom if T = 300 K? Calculate the diffusion constant at this pressure. Assume that Kr obeys the ideal gas law even at these high pressures.

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Solution Mean free path 2 316 1010m Volume 1 L Volume of ... View the full answer