At what temperature $($in $K)$ will the equilibrium constant for the formation of NOCl$(g)$ be equal to $K_p=1\mathrm{.}0{10}^3.$ Data for this reaction at $25C$ are:

$2NO(g)+C{l}_2(g)2$NOCl$(g)$

$G=-40\mathrm{.}9k\frac{J}{m}ol,H=-77\mathrm{.}1k\frac{J}{m}ol,S=-121\mathrm{.}3\frac{J}{m}ol.K$

$S=-121\mathrm{.}3\frac{J}{m}ol.K$

a$)346$

b$)411$

c$)489$

d$)502$

e$)431$