Question: azu + de-Bx au Solve k = at' (B >0, 0 0), u(0, t) = 0, u(1, t) = 0, t>0 u(x, 0) = f(x),

azu + de-Bx au Solve k = at' (B >0, 0 0),
azu + de-Bx au Solve k = at' (B >0, 0 0), u(0, t) = 0, u(1, t) = 0, t>0 u(x, 0) = f(x), 0 0). Demonstrate details of derivations

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