b

STEPS TO SOLVE A LINEAR SYSTEM OF 3 EQUATIONS IN 3 VARIABLES: Step 1: Write all equations in Standard to and label them (1), (2), and (3). Step 2: Pair (1) and (2) together and (2) or (1) with (3) and check for 20 . If not, multiply one, or both, equations by any factors to create zero pairs. Pairs Step 3: Add the equations, in their separate pairings, to eliminate one of the variables, making sure it's the same variable in each pair of equations. This leaves 2 equations in 2 variables. Step 4: (@6 1 ) the two new equations (4) and (5) and pair them together to find or make zero pairs and eliminate another variable. Solve for the other variable. Step 5: variable. Substitute the found variable back into either (4) or (5) to solve for the other Step 6: Back substitute both variables that have been found into one of the three equations, (1), (2), or (3), then solve for the last variable. Answer is given as (x,y,z). an Solve each system by elimination. Check your answers. 1 ex + 5y + 6z =1 2 x + y + 2 = 15 -2x + 5y- 3z = -5 2 0-3X - y+ 52 =4 3-2x - 3y = 9 3 -4x + y + 32 = -7 (- 3 , -1, 2 ) Axt Sy+ 62 =17 ( 5 ) 2 (- 1 ) + 6 2 = 10 74+62 = 10 + 2 Z = 4 X , yz Say +62 210 ( - 3 , - 1, 2 ) 4 - 204 - 67: 80 ( 3 ) - 2 x - 30-1=G -2 x + 3 = 9 - 18 1=18 10 - 1= 6 1= (X = -3