Below are the two tables you will need for this exam.

$\backslash$table$[[$Number of Observations in Subgroup n$,$A$2,$B$2,$D$3,$D$4,$C$3],[2,1\mathrm{.}88,0\mathrm{.}88,0\mathrm{.}00,3\mathrm{.}27,0\mathrm{.}00],[3,1\mathrm{.}02,0\mathrm{.}86,0\mathrm{.}00,2\mathrm{.}57,0\mathrm{.}00],[4,0\mathrm{.}73,0\mathrm{.}84,0\mathrm{.}00,2\mathrm{.}28,0\mathrm{.}00],[5,0\mathrm{.}58,0\mathrm{.}82,0\mathrm{.}00,2\mathrm{.}11,0\mathrm{.}00],[6,0\mathrm{.}48,0\mathrm{.}80,0\mathrm{.}00,2\mathrm{.}00,0\mathrm{.}00],[7,0\mathrm{.}42,0\mathrm{.}77,0\mathrm{.}08,1\mathrm{.}92,0\mathrm{.}50],[8,0\mathrm{.}37,0\mathrm{.}75,0\mathrm{.}14,1\mathrm{.}86,0\mathrm{.}51],[9,0\mathrm{.}34,0\mathrm{.}73,0\mathrm{.}18,1\mathrm{.}82,0\mathrm{.}52],[10,0\mathrm{.}31,0\mathrm{.}71,0\mathrm{.}22,1\mathrm{.}78,0\mathrm{.}53],[11,0\mathrm{.}29,0\mathrm{.}68,0\mathrm{.}26,1\mathrm{.}74,0\mathrm{.}55],[12,0\mathrm{.}27,0\mathrm{.}66,0\mathrm{.}28,1\mathrm{.}72,0\mathrm{.}55],[13,0\mathrm{.}25,0\mathrm{.}64,0\mathrm{.}31,1\mathrm{.}69,0\mathrm{.}56],[14,0\mathrm{.}24,0\mathrm{.}62,0\mathrm{.}33,1\mathrm{.}67,0\mathrm{.}57],[15,0\mathrm{.}22,0\mathrm{.}60,0\mathrm{.}35,1\mathrm{.}65,0\mathrm{.}57],[16,0\mathrm{.}21,0\mathrm{.}57,0\mathrm{.}36,1\mathrm{.}64,0\mathrm{.}57],[17,0\mathrm{.}20,0\mathrm{.}55,0\mathrm{.}38,1\mathrm{.}62,0\mathrm{.}58],[18,0\mathrm{.}19,0\mathrm{.}53,0\mathrm{.}39,1\mathrm{.}61,0\mathrm{.}58],[19,0\mathrm{.}19,0\mathrm{.}51,0\mathrm{.}40,1\mathrm{.}60,0\mathrm{.}59],[20,0\mathrm{.}18,0\mathrm{.}49,0\mathrm{.}41,1\mathrm{.}59,0\mathrm{.}59]]$

A product is made up of three components and all three must operate in order for

the product to operate. The reliability of the three components are: $0\mathrm{.}89,0\mathrm{.}77,$ and

$0\mathrm{.}83.$ What is the probability that the product will operate?

Round your answer to three decimal points. Enter $0\mathrm{.}010$ as $0\mathrm{.}010$ and not as $1\%.$

Your Answer:

A product is made up of three components and all three must operate in order for

the product to operate. The reliability of the three components are: $0\mathrm{.}89,0\mathrm{.}77,$ and

$0\mathrm{.}83.$ What is the probability that the product will operate?

Round your answer to three decimal points. Enter $0\mathrm{.}010$ as $0\mathrm{.}010$ and not as $1\%.$

Your Answer: