BlockPy: #$22\mathrm{.}2)$ Weekend Off

The function cut$\_$day is supposed to consume a string representing the current day of the week, and then produce the current day without the "day" part at the end $($e$.$g$.,"$ from cisc$108$ import assert$\_$equal

day$\_$of$\_$week $=$ "Wednesday"

def cut$\_$day$()$:

return day$\_$of$\_$week$[$:$-3]$

assert$\_$equal$($cut$\_$day$(),$ "Wednes"$)$

assert$\_$equal$($cut$\_$day$(),$ "Thurs"$)$

assert$\_$equal$($cut$\_$day$(),$ "Satur"$)$