Question: Can someone write clearly the answer to part 4. An 8.00-kg particle moves from the origin to position (@, having coordinates x = 5.00 m

Can someone write clearly the answer to part 4.

Can someone write clearly the answer to part 4. An 8.00-kg particlemoves from the origin to position (@, having coordinates x = 5.00

An 8.00-kg particle moves from the origin to position (@, having coordinates x = 5.00 m and y = 5.00 m as shown in the figure. One force on the particle is the gravitational force acting in the negative y direction. Using the equation (W = FAr cos 8 = F . AP), calculate the work done by the gravitational force in going from O to along the following paths. y (m) C B (x, y) - x (m) (A A (a) the purple path (oC, (b) the red path (o(BC, (c) the blue path (o@) (d) Your results should all be identical. Why? Part 1 of 6 - Conceptualize Think about carrying a gallon of milk from the ground floor up a staircase to the third floor, and then along the corridor to your room. The work you do will be several hundred joules, and the work done by gravity in the lifting process will be a value equal in magnitude to your work but opposite in direction. Part 2 of 6 - Categorize We apply the definition of work by a constant force, add up the amounts of work over sequential displacements, and keep track of the results.Part 3 of 6 - Analyze The gravitational force is downward with magnitude Fg = mg - 8 8 kg) (9.80 m/s2) 78.4 $ 78.4 N. (a) The work on the path O@ @ is the sum of the work on paths @ and @as follows. NOAG = WOO + w By the definition of work as force times displacement, we have the following, where do and d are the lengths of segments @ and o, respectively. = Fg doa CO5 90 2 30 ) + F ,d cos 180 2 180 . Substituting the values we know for the gravitational force, the angles, and the lengths of the paths, we have 78.4 P 78.4 N) 5 2 5 m )(0) + 5 x 8 78.4 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. N) (5 0 5 m)(-1) = -392 -392 Part 4 of 6 - Analyze [b) We perform the same calculations for a trip by way of point (B. = WOR + W (78.4 N) (5.00 m)cos *-1 X Your answer cannot be understood or graded. More Information jo + (78.4 N) (5.00 m)cos 78.4 x Your response differs from the correct answer by more than 10%. Double check your calculations." = -392 Submit Skip (you cannot come back)

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