Comment the following assembly code to explain what each line is doing. Then in an equation, express the return value $($v$0)$ as a function of the input arguments $($a$0,$ a$1).$

new$-$proc:

blt $a$1,$ $zero, loop$2$

loop$1$:

beq $a$1,$ $zero, proc$-$end

sll $a$0,$ $a$0,1$

addi $a$1,$ $a$1,-1$

j loop$1$

loop$2$:

beq $a$1,$ $zero, proc$-$end

srl $a$0,$ $a$0,1$

addi $a$1,$ $a$1,1$

j loop$2$

proc$-$end:

add $v$0,$ $a$0,$ $zero

jr $ra