Comparing full$-$wave centre$-$tap rectifiers with half & full$-$wave bridge rectifiers:$$

The $$Blank $1$ Question $4$ makes better use of the transformer$$s secondary than the $$Blank $2$ Question $4$ rectifier, since the transformer$$s full winding supplies power during $$Blank $3$ Question $4$ half cycles, while each half of the centre$-$tap circuit$$s secondary provides power only during its positive half$-$cycle. This is often referred to as the transformer $$Blank $4$ Question $4$ factor, which is unity for the bridge configuration and $0\mathrm{.}5$ for the full$-$wave centre$-$tap configuration.

The $$Blank $5$ Question $4$ rectifier is often not as popular as the full$-$wave centre$-$tap rectifier in $$Blank $6$ Question $4-$current, low$-$voltage applications. This is because the $$Blank $7$ Question $4$ series$-$diode voltage drops in the bridge introduce a volt or more of additional loss, and thus consume $$Blank $8$ Question $4$ power $($heat loss$)$ than a single diode would within a full$-$wave rectifier.

Both circuits have almost the same rectifier requirements. However, the centre$-$tap version has $$Blank $9$ Question $4$ the number of diodes as the bridge. These diodes will however require twice the maximum inverse $$Blank $10$ Question $4$ ratings of the bridge diodes $($PIV $>2\mathrm{.}8$ V $,$ as opposed to $>1\mathrm{.}4$ V$).$ The diode $$Blank $11$ Question $4$ ratings are identical for the two circuits.$$

In $50-60$Hz rectification applications the $$Blank $12$ Question $4$ rectifier configuration is rarely used other than for bias supplies.$$ In $$Blank $13$ Question $4$ switching power supplies in what are called forward converter and fly$-$back converter topologies, It does however see considerable use.

full$$bridge centre$$tap both utilisation half voltage current bridge high two$$forward$$conducting currents more half$$bridge high$$frequency $$less $$salient$$bridge $$low$$frequency

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A rectifier as per the circuit in the following link$$operates at an rms output current of $0\mathrm{.}4097$A

Question: Calculate the average Power dissipated by the load resistance.

Answer:Question $5$ Select one unitChoose...WmW

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A rectifier as per the circuit in the following link$$operates with a load resistance such that it has an average output current of $1\mathrm{.}125$A

Question: Calculate the Power dissipated by the load.

Answer:Question $6$ Select one unitChoose...WmW