complete the code:

function project$\_4()$

$\%$ PROJECT$\_4$ project$\_4()$calculates the resultant force acting at a point.

$\%$

$\%$ All multiplications, divisions, and exponentiations must use the

$\%$ dot operator.

$\%$

$\%$ All code should be tabbed in once $($as the template shows$)$ and aligned

$\%$

$\%$

$\%$ Name:

$\%$ Date:

$\%$ CMPSC $200$

$\%$

$\%$

$\%$

$\%$ Header Information

fprintf$(\text{'}$Name: $\%$s

$\text{'},$ 'Your name'$)$;

fprintf$(\text{'}$Class:CMPSC $200$

$\text{'})$;

fprintf$(\text{'}$Date: $\%$s

$\text{'},$ 'date'$)$;

fprintf$(\text{'}$

$\text{'})$

$\%$ Description of the program

fprintf$(\text{'}\text{'})$;

fprintf$(\text{'}$

$\text{'})$

$\%$ Have the user enter the three forces that are acting on the beam

$\%$ and the angle for each one

$\%$ that each one makes $-$ the first one is done

F$1=$ input$(\text{'}$Enter the first force: $\text{'})$;

A $=$ input$(\text{'}$Enter the angle at which the force acts on the beam: $\text{'})$;

$\%$ You now have to repeat this for F$2$ with angle B$,$ and F$3$ with angle C

$\%$ Decompose each force into its x and y direction components

$\%$ There will be six calculatons $-$ two for each force

$\%$ As an example

F$1$x $=$ F$1.*$ cosd$($A$)$

$\%$ Add the three x direction forces $-$ this sum is the resultant in

$\%$ the x direction $-$ call the variable FRx

$\%$ Add the three y direction forces $-$ this sum is the resultant in

$\%$ the y direction $-$ call the variable FRy

$\%$ Calculate the resultant force using the appropriate formula $-$ Call

$\%$ this variable FR

$\%$ Calculate the angle of the resultant force using the inverse

$\%$ tangent $($atand$(...))-$ this is D

$\%$ Print the results using fprintf so that the data is formatted to two

$\%$ decimal places and are aligned on their decimal points

$\%$ This will include the entered force and the angle, and the x and y

$\%$ components for the force

$\%$ Print so that the first force is on the first row, the second force

$\%$ is on the second row and the third force is on the third

$\%$ The resultant force will be printed on the fourth row

end