compute the value $of$ the improper integral. ${\displaystyle \underset{2}{\overset{}{}}}\frac{dx}{(8x-3{)}^6}=$ use you answer $to$ help determine whether the series ${\displaystyle \underset{n=2}{\overset{}{}}}\frac{1}{(8x-3{)}^6}$ converge $or$ diverges.