computer archeticture | use 2 way set associative mapping, the answer should be the same as the second picture i want to know how to get to that answer, please explain in steps i asked many times on this app and no one gave me the right answer, its urgentthank you.

memory size = 2^24 bit

Cache size = 2^16 bit

1 block = 2^2 bit words

Given the following: -Mapping type: Set Associative Mapping -Memory size: 2m3=224bit -Cache size: Gats 2 bit 1 block: 1 word =1 byte 4 words 22 bit -Addressable unit: word Find: 1- Cache address format 2- Memory address format 3- Address length 4- Number of addressable units 5- Block or line size 6- Number of blocks in main memory 7- Number of lines in set 8-Number of sets 9-Number of lines in cache 8- Size of tag ef Given the folllowing information: - Mapping enpe: 2. way sole Associative Mapping 2=4 - Memorss Ze.16mB16mw6mhrlack=8kset - I Blect in wirds y=x=2 - 1 wira i butes - addressable mit; word D) Find: (1) Cache address format \begin{tabular}{|c|c|c|} \hline Tag & set & w \\ \hline \end{tabular} (2) Memory addiese tormat Set Associative Mapping Summary - Address length =(s+w) bits - Number of addressable units =2s+w words or bytes - Block size = line size =2w words or bytes - Number of blocks in main memory =2s - Number of lines in set =k - Number of sets =v=2d - Number of lines in cache =kv=k2d - Size of tag =(sd) bits