Question: Consider 1 g(x) = 2 0 Consider (a) (b) 2 0 o < xS1 Show that g(x) has a 3-cycle. Show that g(:r) does not


Consider 1 g(x) = 2 0
Consider (a) (b) 2 0 o < xS1 Show that g(x) has a 3-cycle. Show that g(:r) does not have a fixed point or a periodic point of order 2. Why does this not contradict the Li-Yorke Theorem?
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