Question: Consider a 100 mol mixture that is 81.0% methane (CH) and 19.0% ethane (CH). To this mixture is added 21.0% excess air. Of the methane


Consider a 100 mol mixture that is 81.0% methane (CH) and 19.0% ethane (CH). To this mixture is added 21.0% excess air. Of the methane present, 91.30% reacts, 91.90% of which forms carbon dioxide (CO2), and the balance forms carbon monoxide (CO). Of the ethane present, 84.8% reacts, 91.90% of which forms carbon dioxide, and the balance forms carbon monoxide. What is the theoretical amount of oxygen required for the fuel mixture? moles of 02: What amount of air is added to the fuel mixture? moles of air: How many moles of methane are present in the product gas? moles of CH, How many moles of ethane are present in the product gas? moles of C,H How many moles of carbon dioxide are present in the product gas? moles of CO2 How many moles of carbon monoxide are present in the product gas? moles of CO: How many moles of carbon monoxide are present in the product gas? moles of CO: How many moles of water vapor are present in the product gas? moles of H,O: How many moles of oxygen are present in the product gas? moles of 02: How many moles of nitrogen are present in the product gas? moles of Nz
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