Consider a $4$ m long zero weight diving board which is supported at two points along its length, separated by $1\mathrm{.}5$ m $.$ If a $50$ kg man is standing at the end of the board, $2\mathrm{.}5$ m from his nearer support, then how much force does that support apply to the board to maintain static equilibrium? Note that it may be convenient to treat the support farther from the man as the pivot point. The answer of course is independent of the choice of the pivot point. Assume $g=10\frac{m}{s^2}$

$1250$ N

$2000$ N m

$1333$ N

$667$ N

$833$ N