Tutorial Exercise pressure and the area: $F=r^{2}p.$

$$

The work done by the gas when the volume expands from volume $V_1$ to volume $V_2$ is as follows.

$w={\displaystyle \underset{V_1}{\overset{V_2}{}}}PdV$

of $1200i{n}^3.$

Step $1$

We know that $P{V}^{1\mathrm{.}4}=k$ and that the work can be calculated as $W={\displaystyle \underset{V_1}{\overset{V_2}{}}}PdV.$

The steam starts at pressure $P=130l\frac{b}{i}{n}^2,$ volume $V_1=400i{n}^3$ and volume $V_2=1200i{n}^3.$

Converting inches to feet gives us $P=130(l\frac{b}{f}{t}^2,v_1=f{t}^3,$ and $v_2=1200$

$f{t}^3$