Consider a five$-$sided closed polygon traverse. A$=1324706"$A$=1324706",$ B$=1084618"$B$=1084618",$ C$=1071937"$C$=1071937",$ D$=815036"$D$=815036",$ E$=1091618"$E$=1091618".($Note: line BCBC bears SE$.)$ The lengths of the sides $($in feet$)$ are as follows: AB$=202\mathrm{.}74$AB$=202\mathrm{.}74,$ BC$=283\mathrm{.}87$BC$=283\mathrm{.}87,$ CD$=498\mathrm{.}37$CD$=498\mathrm{.}37,$ DE$=320\mathrm{.}33$DE$=320\mathrm{.}33,$ and EA$=380\mathrm{.}78$EA$=380\mathrm{.}78.$ The coordinates of station AA are X$=20,000\mathrm{.}00$ftX$=20,000\mathrm{.}00$ft and Y$=15,000\mathrm{.}00$ftY$=15,000\mathrm{.}00$ft$.$

Part A

Compute the area enclosed by the traverse above using DMDs$.$

Express your answer in feet squared to five significant figures. Note: Traverse does not need to be adjusted to determine the correct answer.