Question: Consider a mixture of n - hexane ( 1 ) and n - heptane ( 2 ) that is 3 5 % mole n -

Consider a mixture of n-hexane (1) and n-heptane (2) that is 35% mole n-heptane in the liquid phase and at a pressure of 101.325kPa.
Determine the system temperature and the vapor phase mole fractions. In case of iteration, use the initial value of T as T=x1T1sat+x2T2sat. Show complete solution for the 1st iteration, and for the final values of vapor phase mole fractions. State all your assumptions and the justifications of your assumptions. (20 points)
Consider a low-vapor pressure binary system (consisting of species 1 and species 2) in vapor-liquid equilibrium. The liquid phase is an equimolar mixture. If activity coefficients are given by ln1=Ax22 and ln2=Ax12 and the modified Raoult's Law is valid, prove that the mole fraction of species 1 in the vapor phase is given by
y2=1-P1satP1sat+P2sat
where i= activity coefficients,
Pisat= pure species vapor pressure of component i
xi= mole fraction in liquid phase
yi= mole fraction in vapor phase
Show your complete solution. Start solution from the Modified Raoult's Law. (10 points)
 Consider a mixture of n-hexane (1) and n-heptane (2) that is

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Chemical Engineering Questions!