Consider a parallel plate capacitor made from a 1mm thick 1m2 area BaTiO3 dielectric layer sandwiched between two nickel electrodes. If the dielectric constant () of BaTiO3 is 1000 , the capacitor will have a capacitance (C) of 0.01F. If the BaTiO3 layer's thickness is cut in half (0.5mm thickness 1m2 area) what happens to and C ? Dielectric Constant =1000:C=0.02F Dielectric Constant =1000:C=0.005F Dielectric Constant =500;C=0.01F Dielectric Constant =2000;C=0.01F Dielectric Constant =2000;C=0.005F