Question: Consider five layer system. 1: External air. 2: Cover glass, which is fat cylindrical, has radius of 0.5 cm and 0.3 mm thickness. Assume
Consider five layer system. 1: External air. 2: Cover glass, which is fat cylindrical, has radius of 0.5 cm and 0.3 mm thickness. Assume glass heat capacity C glass = 0.8 J/(g*kelvin). Assume glass thermal diffusivity = 88 mm^2/s 3: Water tissue mixture, which is fat cylindrical, has radius of 0.5 cm and 10 m thickness. Assume water heat capacity C_water = 4 J/(g*kelvin). Assume water thermal diffusivity = 0.15 mm^2/s. 4: Bottom glass, which is fat cylindrical, has radius of 0.5 cm and 1 mm thickness. 5: External air Assume temperature is uniform in z direction at all (x,x) after short time t. Assume no boundary heat transfer property need to be considered. Assume at the center of the layer 3, a cylinder is being heated at constant rate of w J/s, which has radius of 5 m and 10 m thickness. This radius of 5 m and 10 m thickness cylinder reaches 85 Celsius from 20 Celsius after being heated for 35 minutes. Derivate heat gradient equation interms of w,x,y,z,t so that I can plug in w,x,y,z,t to find the specific T in time space. (Feel free to simplify the model for easier calculation)
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ut u Qx y z t where ux y z t is the temperature at point x y z and time t is the thermal diffusivity of the material which is a measure of how quickly heat diffuses through the material is the Laplaci... View full answer
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