Consider the area between the graphs $x+1y=24$ and $x+6=y^2.$ This area can $be$ computed $in$

two different ways using integrals.

First $of$ all $it$ can $be$ computed $as$ a sum $of$ two integrals

${\displaystyle \underset{a}{\overset{b}{}}}f(x)dx+{\displaystyle \underset{b}{\overset{c}{}}}g(x)dx$

where $a=$

$b=$

$,c=$

and

$f(x)=$

$g(x)=$

Alternatively this area can $be$ computed $as$ a single integral

${\displaystyle \underset{}{\overset{}{}}}h(y)dy$

where $=$

$,=$

and

$h(y)=$

Either way $we$ find that the area $is$