Consider the circuit below. Here $V_A=10V,=390$kra$\frac{d}{s},R=5\mathrm{.}0k,$ and $C=8\mathrm{.}5$ nF$.$

What is the root$-$mean$-$square $($RMS$)$ power dissipated by the resistor R$?$ Give your answer in units of mW $.$

Hint: Power is$,$ in general, a time$-$dependent quantity. However in this circuit, as the resistor is driven by a sinusoidal source, the RMS power is given by the following equation.

$P_{\text{a}\text{v}\text{g}}=\frac{1}{2}[P(t){]}_{\text{m}\text{a}\text{x}}$

Your Answer:

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