Consider the following data from two independent samples with equal population variances. Construct a 98% confidence interval to estimate the difference in population means. Assume the population variances are equal and that the populations are normally distributed. X1 = 36.8 X2 = 32.2 $1 = 8.7 $2 = 9.1 n1 = 17 n2 = 18 Click here to see the t-distribution table, page 1 Click here to see the t-distribution table,_page 2 . . .. . The 98% confidence interval is ( (Round to two decimal places as needed.)