Consider the following initial value problem

$y^{\text{'}\text{'}}-3y^{\text{'}}+2y=2$

$y(0)=1$

$y^{\text{'}}(0)=0$

What is the Laplace transform of $y?$

$L\{y\}=\frac{2(s^{})}{(s-2)(s-1)}$

II$.L\{y\}=\frac{s^2-3s+1}{s(s-2)(s-1)}$

III. $L\{y\}=\frac{s^2-3s-1}{s(s-2)(s-1)}$

IV$.L\{y\}=\frac{1}{s}$

v$.L\{y\}=\frac{s-3}{s(s-2)}+\frac{2}{s(s-1)}$