Consider the following L.P. problem. MAX 2x + 3y s.t. 5x + 5y = 0. The x-coordinate of the extreme point with the smallest x-value

Consider the following L.P. problem.

MAX 2x + 3y

s.t. 5x + 5y <= 400 AND -1x + 1y <= 10 AND 1x + 3y >= 90 AND x,y >= 0.

The x-coordinate of the extreme point with the smallest x-value is x =

Another extreme point is where y=5 and x =

A third extreme point is where x =

The optimal solution for this L.P. problem has objective value

If the objective was changed to MAX 2x + 1y then the objective value of the optimal solution will be