Question: Consider the following MIPS code: lbu $t0, 0($t1) sw $t0, 0($t2) Assume that register $t1 contains the address 0x1000 0000, register $t2 contains the address

Consider the following MIPS code:

lbu $t0, 0($t1)

sw $t0, 0($t2)

Assume that register $t1 contains the address 0x1000 0000, register $t2 contains the address 0x1000 0010, and the data at address 0x1000 0000 is 0x11223344. What value is stored at the address pointed to by register $t2 after running the given code? (Note that the MIPS architecture utilizes big-endian addressing

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