Consider the loading of the beam below. The distributed load is defined by the function

w$=$kx$1\mathrm{.}5.$ The pin at A is double$-$shear and the pin at B and D are single$-$shear.

$$ Using a factor of safety of $1\mathrm{.}5$ and knowing that each pin is made of Tool Steel L$-2,$

calculate an appropriate safe diameter for each pin, and report your answer to the

nearest $1/16$ of an inch.

$$ Also, if rod BD must be made of A$-36$ steel, again using a safety factor of $1\mathrm{.}5,$ calculate

an appropriate diameter for it$.$

$$ Additionally, state if the rod is in compression or tension according to this situation, and

calculate the change in length of the rod BD$,$ is it going to get shorter to longer by that

amount?

Assume the yield shear strength is $58\%$ of the yield tensile$/$compressive strength