Question: Consider the truss shown in the figure. All E = 2 9 1 0 6 . Areas ) are in parentheses. A horizontal force of

Consider the truss shown in the figure. All E=29106. Areas ) are in parentheses. A horizontal force of 86k is applied to the right at joint 4 and the support at joint 3 settles 0.17 inches.
Element Connectivity
\table[[Element,End i,End j,],[1,,,1],[2,,3,4],[3,,2,3],[4,,1,4],[5,,4,2]]
a. Form the element stiffness matrices k(i)2x2,i=1,dots,5 in local coordinates.
b. Form the element coordinate transformation matrices, (i),i=1,dots,5.
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c. Form the element global stiffness matrices, kg(i),i=1,dots,5.
d. Form the K-,Kr,Krr sub-matrices of the partitioned
global stiffness matrix. Use the global variable numbering scheme shown in the table at the right.
e. Solve for the unrestrained global displacements and reactions. Show them on a figure. whether member 2 is in tension or compression.
Consider the truss shown in the figure. All E = 2

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