Consider this differential equation for y = y(x): (*) dy = dz 1+y2 1+22 Find the general solution, and use it to complete parts (a)-(c) below. (a) Find the solution y(z) for (*) that satisfies the additional requirement y(0) = 0. Determine the largest open interval containing z = 0 on which the identity () is valid. (Use interval notation to enter your answer; type "inf" to represent co.) y(2) = , for E (b) Repeat part (a), but use the modified initial condition y(0) = -5. y(x) = for E (c) Repeat part (a), but use the modified initial condition y(0) = 5. v(z) for E