Question: correct answer is 37620000 channels open kindly solve it correctly to get upvote 2. During the upstroke of an action potential in squid giant axon,

correct answer is 37620000 channels open
kindly solve it correctly to get upvote
2. During the upstroke of an action potential in squid giant axon, the probability of a sodium channel being open changes. At rest the probability of an open channel is 0.01, while at the peak of an action potential it is 0.2. Consider 0.6 mm of cell membrane. On the average, how many channels change from closed to open as the membrane moves from rest to peak, i.e., during the upstroke of the action potential? Table 4.1. Conductance of Sodium and Potassium Channels Preparation Channels (number/um) (ps) Sodium Squid giant axon Frog node Rat node Bovine chromaffin 4 6-8 14.5 17 330 400-2000 700 1.5-10 Potassium Squid giant axon Frog node Frog skeletal Mammalian BK 12 2.7-4.6 15 130-240 30 570960 30 Coulombs per um?. Multiplication by Avogadro's number and division by the Faraday results in 6200 monovalent ions required per pm. One channel carrying 1 pA of current moves that many ions in 1 msec. Thus the "sparse" channel density in Table 4.1 is also several orders greater than an absolute minimum
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