Question: Could a get some help with the steps to solving this? Thanks The polynomial of degree 3, P(a), has a root of multiplicity 2 at

Could a get some help with the steps to solving this?

Could a get some help with the steps to solving this? Thanks

Thanks The polynomial of degree 3, P(a), has a root of multiplicity

The polynomial of degree 3, P(a), has a root of multiplicity 2 at a = 3 and a root of multiplicity 1 at x = - 3. The y-intercept is y = - 2.7. Find a formula for P(x). P(a) =

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