Could you please solve this question and point out my mistakes? My answer is: X~N(1300,10^2), then standard the normal distribution (X-1300)/10 ~ N(0,1), thus P(X

A manufacturer of a high-performance road bike tyres has evaluated that the distance cycled on their new tyre before the rubber wears down and requires replacing is Normally distributed with a mean of 1300 miles and a standard deviation of 10 miles. As part of their promotional material the manufacturer would like claim that "90% of our new tyres will travel x miles before replacement". What is the distance x, in miles, that the manufacturer should quote? 1307 1300 X 1287 1284 O 1293 The correct answer is: 1287 A retail store records the number of people that enter their store. The average rate of people entering their store is 112 per hour. Let X be th