Question: Create a java class for a circular singly linked list, where the last node connects back to the first node. In this circular list: There

Create a java class for a circular singly linked list, where the last node connects back to the first node. In this circular list:
There is no specific "start" or "end."
Instead, the only access to the list is through a reference called current, which can point to any node in the list.
Your class should be able to insert new nodes, search for a specific node, and delete a node.
These operations will be performed relative to the current node. That is, the insertion, search, or deletion happens on the node that is one step downstream of the current node.
A method called step() should move the current reference to the next node in the list.
Key Features:
Insertion: Insert a new node right after the node pointed to by current.
Searching: Search for a specific node (by value) starting from current and moving around the circle.
Deletion: Remove the node that comes right after current.
Display: Create a method to display the list. Since its circular, you will need to break the circle at some point to display the nodes in a linear fashion.
Step Method: Move the current pointer to the next node.
Things to Remember:
You cannot access the node before the current one directly, since it's a singly linked list.
The current pointer should be able to move freely around the list in a circular manner.
There is no "beginning" or "end" of the list, as the last node links back to the first.
Example:
Suppose your list contains nodes with values: A -> B -> C -> D -> A (since its circular).
If current points to B and you call the step() method, current should now point to C.
If you insert a node E while current is pointing to C, the list will now be: A -> B -> C -> E -> D -> A.

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