Crude oil flows through the $2-$mm gap between the two fixed parallel

plates shown in $($Figure $1)$ due to a drop in pressure from $A$ to $B$ of $4$

kPa. The plates are $900mm$ wide. Take $=30\mathrm{.}2({10}^{-3})N*\frac{s}{m^2},$

$=880k\frac{g}{m^3}.$

Figure

Please help me with fluid mechanics