Question: d) (6 points) Using the same expression for each of the 9 states, one can determine the values for all ni, i=0...9. The results are

 d) (6 points) Using the same expression for each of the

d) (6 points) Using the same expression for each of the 9 states, one can determine the values for all ni, i=0...9. The results are as follows: no = 2.143, n = 1.484, n = 0.989, 73 = 0.629, 14 = 0.378, ns = 0.210, n = 0.105, 17 = 0,015, n = 0.015, a = 0,003 Plot the n, as discrete points, as function of the E). On the same graph, plot Ae-E, the continuous Boltzmann distribution function, with A = n(E=0) = no, and a=0.43377 (a has been chosen empirically to make the continuous Boltzmann distribution compatible with the coarse, discrete sampling of only 10 energy states up to E =9). The discrete points should lie almost on top of the continuous curve. It is remarkable that the combinatorics of such a small number of particles and energy levels nevertheless begins to reveal the exponential behavior of the Boltzmann distribution, d) (6 points) Using the same expression for each of the 9 states, one can determine the values for all ni, i=0...9. The results are as follows: no = 2.143, n = 1.484, n = 0.989, 73 = 0.629, 14 = 0.378, ns = 0.210, n = 0.105, 17 = 0,015, n = 0.015, a = 0,003 Plot the n, as discrete points, as function of the E). On the same graph, plot Ae-E, the continuous Boltzmann distribution function, with A = n(E=0) = no, and a=0.43377 (a has been chosen empirically to make the continuous Boltzmann distribution compatible with the coarse, discrete sampling of only 10 energy states up to E =9). The discrete points should lie almost on top of the continuous curve. It is remarkable that the combinatorics of such a small number of particles and energy levels nevertheless begins to reveal the exponential behavior of the Boltzmann distribution

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