Question: Definition: If f(x) is a function, then we say that a value u is a fixed point of f(x) if ar only if f(u)=u .
Definition: If
f(x)is a function, then we say that a value
uis a fixed point of
f(x)if ar only if
f(u)=u.\ Suppose
F(x)is a given continuous function and
a!=0is a given real number.\ a. Show that
uis a zero of
F(x)if and only if
uis a fixed point of
f(x)
f(x)=x+aF(x)\ b. Suppose
F^(')(x)is continuous,
uis a zero of
F, and
F^(')(u)!=0. Define
f(x)=x+aF(x). Prove there are values of
a!=0and
\\\\epsi >0so that if
u_(0)in
(u-\\\\epsi ,u+\\\\epsi )and
u_(n+1)=f(u_(n))for
n=0,1,2,dotsthen
u_(n)->uas
n->\\\\infty . Hint:
|u_(n+1)-u|=|f(u_(n))-f(u)|. Use the definition of
f(x)and the mean value theorem.

Definition: If f(x) is a function, then we say that a value u is a fixed point of f(x) if a only if f(u)=u. Suppose F(x) is a given continuous function and a=0 is a given real number. a. Show that u is a zero of F(x) if and only if u is a fixed point of f(x) f(x)=x+aF(x) b. Suppose F(x) is continuous, u is a zero of F, and F(u)=0. Define f(x)=x+aF(x). Prove there are values of a=0 and >0 so that if u0 (u,u+) and un+1=f(un) for n=0,1,2, then unu as n. Hint: un+1u=f(un)f(u). Use the definition of f(x) and the mean value theorem
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