DES.

For notational simplicity, assume it is the first round.

Please enter all answers as strings of $0\text{'}$s and $1\text{'}$s$.$

The input is the $64$ bit block

$0000000000000000100000101000010000000000000000000000000000100000$

Suppose that the subkey for the current round is this $48$

bit number:

$000100000000000000000000000000000000000000000000$

What does the $64$ bit state look like after the IP

transformation is applied to the input?

Now find $L_0$ and $R_0,$ the left and right halves of the

state.

$L_0=$

$R_0=$

What is the result of applying the expansion box to $R_0?$

$E(R_0)=$

What is the result of XORing the subkey with $E(R_0)?$

$k_{1}o+E(R_0)=$

We now apply the S$-$box transformation.

$S(k_{1}o+E(R_0))=$

Finally we apply the permutation box to complete the

function $f.$

$f(R_0)=P(S(k_{1}o+E(R_0)))=$

We can now compute the state of DES going into the

next round.

$L_1=$

$R_1=$

Solve this problem please