Question: Describe where and what the error in this code is. IFNOT index_error AND NOT type_error THEN OUT_Job_Index:=job_index ELSE OUT_Job_Index:=0; ELSIFNOT index_error AND type_error THEN OUT_Job_Index:=-2;

Describe where and what the error in this code is. IFNOT index_error AND NOT type_error THEN OUT_Job_Index:=job_index ELSE OUT_Job_Index:=0; ELSIFNOT index_error AND type_error THEN OUT_Job_Index:=-2; END_IF
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