Dianelys is older than Lillian. Their ages are consecutive integers. Find Dianelys's age if the sum...

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Dianelys is older than Lillian. Their ages are consecutive integers. Find Dianelys's age if the sum of the square of Dianelys's age and 2 times Lillian's age is 118. Dianelys is older than Lillian. Their ages are consecutive integers. Find Dianelys's age if the sum of the square of Dianelys's age and 2 times Lillian's age is 118.

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Lets denote Dianelyss age as x and Lillians age as x 1 since ... View the full answer